Re: another help on input record separator clarity please

On Fri, May 2, 2008 at 5:08 PM, Joshua Hoblitt <jhoblitt@[EMAIL PROTECTED]
>
wrote:
snip
>  They are probably undefinately because the record seperator is being
set
>  lexically inside of the loop (and thus won't apply to the outer while).
 Please
>  consider this code:
>
>
>     local $/ = "\n\n";
snip

An im****tant nitpick: that is a localized version of $/, not a lexical
version.  See

http://perldoc.perl.org/functions/local.html

for more information.

-- 
Chas. Owens
wonkden.net
The most im****tant skill a programmer can have is the ability to read.