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Programming > Perl Beginners > a declaring
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a declaring

by peng.kyo@[EMAIL PROTECTED] (J. Peng) Apr 21, 2008 at 10:40 PM

I'm not sure, but why this can work?

use strict;
use warnings;
use Data::Dumper;

my $y=0;
my @[EMAIL PROTECTED]
 =(1,2,3) if $y;
print Dumper \@[EMAIL PROTECTED]
 $y is false, it seems @[EMAIL PROTECTED]
 shouldn't be declared.
But why the last print can work?

-- 
J. Peng - QQMail Operation Team
eMail: peng.kyo@[EMAIL PROTECTED]
  AIM: JeffHua




 8 Posts in Topic:
a declaring
peng.kyo@[EMAIL PROTECTED  2008-04-21 22:40:19 
Re: a declaring
noreply@[EMAIL PROTECTED]  2008-04-21 17:37:20 
Re: a declaring
noreply@[EMAIL PROTECTED]  2008-04-21 17:54:23 
Re: a declaring
chas.owens@[EMAIL PROTECT  2008-04-21 13:21:46 
Re: a declaring
noreply@[EMAIL PROTECTED]  2008-04-21 22:12:37 
Re: a declaring
chas.owens@[EMAIL PROTECT  2008-04-21 13:58:28 
Re: a declaring
peng.kyo@[EMAIL PROTECTED  2008-04-22 09:25:38 
Re: a declaring
chas.owens@[EMAIL PROTECT  2008-04-21 21:27:17 

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tan12V112 Thu May 15 0:25:03 CDT 2008.