"roofy" <rneilen216@[EMAIL PROTECTED]
> wrote in message
news:1180800856.979324.321980@[EMAIL PROTECTED]
'm a little rusty on Pascal, but let's have a go...
> What I do not understand in the first variable is the = (PAWN, ROOK,
> KNIGHT ...etc. How could one variable equal another undefined variable
> not to mention that their are six undefined variables that point to
> PieceImageType.
It's not a variable, it's a defining a new data type. One which can have
one of six values, those values being PAWN, ROOK, and so on.
In C:
enum PieceImageType {PAWN, ROOK, KNIGHT, BISHOP, QUEEN, KING};
> The second defined variable is that I do not
> understand the concept of how the programmer was defining
> PossibleMoves as an array. If I understand correctly, when defining an
> array, the part that is inside the brackets is what defines the size
> of the array.
I'm assuming that the PossibleMoveType as in the Type section along with
PieceImageType rather than the Var section.
So, it's defining a type PossibleMoveType which is a six element array
with
indexes PAWN, ROOK, and so on.
And, later there should be something like
Var Moves: PossibleMoveType;
which would then permit, in the code section:
Moves[ROOK].NumDirections := 3;
Moves[KING].UnitMove[3].DirRow := -1;
or there might be:
ThisPiece: PieceImageType;
in the Var section, allowing this usage in the code section:
ThisPiece := BISHOP;
if Moves[ThisPiece].MaxDistance = 3 then
and so on.
- Bill
|
