On 2008-04-30, Maury Pepper <mpepper_scram_spam@[EMAIL PROTECTED]
> wrote:
> There is no operator precedence in Mumps so the expression "if i<j&k>j"
is
> evaluated as:
> if (((i<j)&k)>j)
> Since 1 is less than 2, the first term is true, and "true" has the value
1.
> Since 1 & 3 is true, the second term is true, ie = 1.
> Since 1 is not greater than 2, the third term is false.
I see now! The moral of the story then is:
Put the parentheses where _you_ want/need them and _never_ rely on Mumps
to do it! ;)
Thanks!!
> "Duke Normandin" <dukeofperl@[EMAIL PROTECTED]
> wrote in message
> news:pURRj.3093$PM5.3083@[EMAIL PROTECTED]
>> set i=1,j=2,k=3
>>write "yes",!
>>
>> i _is_ less than j AND k _is_ greater than j
>>
>> so why is _yes_ NOT printed?
>>
>> The logical operator & tells me that both relational expressions must
>> be true in order for the _yes_ to be printed. That's exactly what it
is,
>> so what am I missing? TIA......
>> --
>> Duke Normandin
--
Duke Normandin
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