Re: True Integer, Double

RC wrote:
> Heaveno (Not Hello),
> 
> How do I make sure a number is a TRUE Integer or TRUE Double?
> 
> i.e
> Integer integer = new Integer("1"); // TRUE
> 
> Integer integer = new Integer("1.0");
> // NOT TRUE, NumberFormatException couldn't catch it
> 
> Double d = new Double("1.0"); // TRUE
> 
> Double d = new Double("1");
> // NOT TRUE, NumberFormatException couldn't catch it

     I'm not quite sure what you mean by "TRUE," since "1"
seems like a perfectly good Integer to me, just as "1.0"
and "1" seem like perfectly good Doubles.

     I'm also perplexed at "NumberFormatException couldn't
catch it."  In the case of `new Double("1")' there should be
no exception thrown, because there's nothing wrong with "1"
as a Double.  But for `new Integer("1.0")' there should be a
NumberFormatException, and you should be able to catch it if
you want to.

     Try explaining your notion of "TRUE" a bit more, and/or
consider using java.text.NumberFormat.

-- 
Eric.Sosman@[EMAIL PROTECTED]