Re: access levels for private field which is inherited

On Sun, 13 Apr 2008 09:37:03 -0700, Mark Space wrote:


> Anyway, calling super here is probably the best choice. Note than in
> your example you must call super because Bar has no default constructor.
> 
> One can also provide a factory method such as newInstance below.
> 
> package attribs;
> 
> public class Foo extends Bar {
>    private String id;
>    public Foo(String name,String id){
>      super( name );           // New line here //this.name = name;     
>      // Get rid of this one this.id = id
>    }
>    static public Foo newInstance( String id ) {
>      Foo f = new Foo( "default", id );
>      f.setSomeOtherNonfinalProperty( "non" ); return f;
> }
> 
> package attribs;
> 
> public class Bar {
> 
>    private String name;
> 
>    public setName(String name) {this.name = name;}
> }


Yup, this worked perfectly :)


-Thufir