"Nick" <nachiket.****rwalkar@[EMAIL PROTECTED]
> wrote in message
news:813a8f4e-5823-4682-911d-b4d9d72c75de@[EMAIL PROTECTED]
> Hi,
>
> I have an urgent requirement to be done in JAVA where in I need to
> compare between two directories and to see if there are exact same
> name files available in both the directories. So for eg. DIR1 and DIR2
> both have 1.xml, 2.xml then its fine or re****t the missing ones.
>
> Secondly whichever files are avilable in both the directories compare
> them so compare 1.xml in DIR1 to 1.xml in DIR2 but only on certain
> fields.
>
> So in summary :
>
> DIR1 -> 1.xml{contents= <a>20</a><b>10</b> }, 2.xml, 3.xml
> DIR2 -> 1.xml{contents= <a>25</a> }, 2.xml, 4.xml
>
> Then the re****t should tell me that
>
> a] 3.xml is missing in DIR2
> b] 4.xml is missing in DIR1
> c] <a> field in the 1.xml differs
> d] But assuming <b> is a fields to be ignored do not display any
> error.
>
> Can these be done in JAVA and how ?
>
> Please help.
>
> regards
> Nick
For the first task you essentially need (recursive) directory listings.
You
could start with something like this
(http://exampledepot.com/egs/java.io/GetFiles.html)
and take it from there
(there are useful links). If you convert your file listings to sets you
can
do a difference operation
(http://java.sun.com/docs/books/tutorial/collections/interfaces/set.html)
to
cleanly discover what files are different, and intersections to get the
common file listings.
Once you have common file listings, and given that you are comparing XML
content, you'll be able to find existing programs/utilities that do XML
diffs.
AHS
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