Re: Need some in Hibernate

RC wrote:
> Hello there,
> 
> I am new in Hibernate. I look at some examples in Hibernate 3.2
> There is ALWAYS a Long id in a table class, like
> 
> public class State {
>     private Long id; // no such column in my STATE table in database
>     private String state_code; // two-character state code
>     private String state_name;
> 
>     then six pairs of getXXX/setXXX();
> }
> 
> 
> My question is my existing table in database has NO id column.
> I am NOT allow to altering the existed table.
> 
> How do I do the mapping (How do I re-write my XML mapping file)?
> Thank Q very much in advance!

Apply the name attribute of the id tag in the mapping table to whatever
the 
primary key actually is.  By defining a generator, you are asking
Hibernate to 
generate the primary key for you, obviously not in accordance with the
table's 
design.
<http://www.hibernate.org/hib_docs/v3/reference/en/html/mapping.html#mapping-declaration-id>



If it's a multi-column key, you'd need
<http://www.hibernate.org/hib_docs/v3/reference/en/html/mapping.html#mapping-declaration-compositeid>



The Hibernate folks suggest:
> There is an alternative <composite-id> declaration to allow access to 
> legacy data with composite keys. We strongly discourage its use for
anything else.

I do not get what all this is about "legacy data" and "discourage its
use". 
It's quite common and proper for tables to have multi-column keys.

I haven't run across that editorial outlook in JPA articles (Java
Persistence 
API), for all that JPA is largely based on Hibernate.

-- 
Lew