On Apr 14, 12:54 pm, Vince Hradil <hrad...@[EMAIL PROTECTED]
> wrote:
> On Apr 14, 11:47 am, Conor <cmanc...@[EMAIL PROTECTED]
> wrote:
>
>
>
> > On Apr 14, 10:57 am, Vince Hradil <hrad...@[EMAIL PROTECTED]
> wrote:
>
> > > On Apr 14, 9:16 am, moxam...@[EMAIL PROTECTED]
wrote:
>
> > > > Dear All,
>
> > > > I have the following problem:
>
> > > > I have an array lets say A = [3,4,6,8,3,2,5,7,10,5,4]. As you can
see,
> > > > in this array we have two peaks (8 and 10) and one gap (2). I want
to
> > > > plot this array and draw a line on the gap element (which is in 2)
> > > > vertical on the x axes and parallel to the y axes. In other words,
I
> > > > want to segment the the curve produced by plotting the array by
> > > > drawing a line on the gap element.
>
> > > > Any help will be appreciated.
>
> > > > Thank you very much in advance,
>
> > > > Dabboor
>
> > > Is this what you want:
>
> > > idx = (where(A eq min(A)))[0]
> > > plot, A
> > > plots, [idx,idx], !y.crange
>
> > The slightly quicker way to find the minimum is to just use the second
> > parameter to the min() function:
>
> > minval = min( A, idx )
>
> I always forget that - does it return the first index or an array of
> indexes?
Just the first, unless you use the dimension keyword.
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