On Apr 14, 10:57 am, Vince Hradil <hrad...@[EMAIL PROTECTED]
> wrote:
> On Apr 14, 9:16 am, moxam...@[EMAIL PROTECTED]
wrote:
>
>
>
> > Dear All,
>
> > I have the following problem:
>
> > I have an array lets say A = [3,4,6,8,3,2,5,7,10,5,4]. As you can see,
> > in this array we have two peaks (8 and 10) and one gap (2). I want to
> > plot this array and draw a line on the gap element (which is in 2)
> > vertical on the x axes and parallel to the y axes. In other words, I
> > want to segment the the curve produced by plotting the array by
> > drawing a line on the gap element.
>
> > Any help will be appreciated.
>
> > Thank you very much in advance,
>
> > Dabboor
>
> Is this what you want:
>
> idx = (where(A eq min(A)))[0]
> plot, A
> plots, [idx,idx], !y.crange
The slightly quicker way to find the minimum is to just use the second
parameter to the min() function:
minval = min( A, idx )
|
