On Mar 15, 7:31=A0pm, Vince Hradil <hrad...@[EMAIL PROTECTED]
> wrote:
> On Mar 15, 4:07 pm, Vince Hradil <hrad...@[EMAIL PROTECTED]
> wrote:
>
>
>
>
>
> > On Mar 15, 3:53 pm, Raghu <raghuram.narasim...@[EMAIL PROTECTED]
> wrote:
>
> > > Hi,
>
> > > With reference to my recent posting (IDL batch indexing), i
understood=
> > > that i could structures. However, i haven't been able to figure out
> > > one step.
>
> > > Here is my code as of now:
> > > ; I want to search for all the images(files) in the directory
trials,
> > > read them into the structure named data, and access each file within
> > > the structure.
>
> > > pro strcutres
> > > dir1=3D'D:\trials'
> > > cd,dir1
> > > files=3DFILE_SEARCH('*[^\.{hdr}]', /QUOTE,count=3Dnumfiles)
> > > i=3D0
> > > while i lt numfiles do begin
> > > named=3Dfiles(i)
> > > print,named
> > > data=3D{ID:'a',sizes:fltarr(2179,761)}
> > > data=3Dreplicate(data,numfiles)
> > > data.sizes=3Dfindgen(numfiles)
> > > openr,1,named
> > > readu,1,data[i].sizes
> > > close,1
> > > i=3Di+1
> > > endwhile
> > > end
>
> > > ERROR message- READU: Expression must be named variable in this
> > > context: <FLOAT =A0 =A0 Array[2179, 761]>.
>
> > > I am getting the error here because it seems like i am not able to
> > > read in the LUN 1 or named, into data[i].sizes.
>
> > > Where am i going wrong ?
>
> > > Raghu
>
> > Hoo boy - here you go.
>
> > 1-Yes, you need to use a named variable to readu
> > 2-You already defined "sizes" (weird name, by the way, how about
> > "values"), when you made the structure.
>
> > How about this:
>
> > pro strcutres
> > dir1=3D'D:\trials'
> > cd,dir1
> > files=3DFILE_SEARCH('*[^\.{hdr}]', /QUOTE,count=3Dnumfiles)
>
> > data=3D{ID:'a',values:fltarr(2179,761)}
> > data=3Dreplicate(data,numfiles)
> > tempval =3D fltarr(2179,761)
>
> > for i=3D0L, numfiles-1 do begin
> > named=3Dfiles(i)
> > print,named
>
> > openr,1,named
> > readu,1,tempval
> > free_lun,1
> > data[i].values =3D tempval
>
> > endfor
>
> > return
> > end
>
> BTW - why do you want to use a structure again? =A0The above code makes
> all the data.id's =3D 'a'.
>
> Why can't you just read the data into a matrix? =A0If you want the
> structure to contain the filename then add data[i].id =3D named inside
> the loop.- Hide quoted text -
>
> - Show quoted text -
Hi,
Are you asking why i'm using structures in the first place ?
If yes, my initial idea (from python lessons) was to create something
like an empty array and then read in each file into this empty array
by concatenation. That way each element would have a unique ID which i
could use to access them.
But it seems like i can't create an empty 2-d array of a certain size
and number of files to be read ('numfiles' in my case).
When you say create a matrix, is this what you meant ?
I got the idea of using structures only from responses in my previous
emails on 'batch indexing'.
-R
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