Re: Two dimensional array Question

mdh wrote:


> int main (int argc, const char * argv[])
> 	{
> 	int i, j, k, l;
> 	char arr [3][3] = {"One", "Two", "Lst"};

You do not reserve enough space for a null terminator. You will have
arrays of char but not strings in your array.

> 	char *p;
> 	char **q;
> 
> 	for ( i = 0; i < 3; i ++)
> 		for ( j= 0; j < 3; j++)
> 		{
> 		p=&arr[i][j];
> 	printf( "%p\n", p);

You should cast p to void*.

> 		}
> 
> 	putchar('\n');
> 
> 	for ( k = 0; k < 3; k ++)
> 		for ( l= 0; l < 3; l++)
> 		{
> 			p=arr[k];
> 			q=&arr[k][l];
> 		printf( "%s %s\n", p, q);

You attempt to pass the non-strings when printf() is expecting strings.
Your program now exhibits undefined behavior. Nothing else about it
will tell you very much.



Brian