Re: Two dimensional array Question

pete <pfiland@[EMAIL PROTECTED]
> writes:

> Ben Bacarisse wrote:
>> pete <pfiland@[EMAIL PROTECTED]
> writes:
<snip>
>>> But it's better if you realize that
>>>
>>>     *p = arr[i];
>>>
>>> means the same thing as
>>>
>>>     *p = &arr[i][0];
>>
>> The trouble is this phrase "means the same as".  Both right hand sides
>> are certainly closely related expressions, but they have different
>> types, different sizes (sizeof arr[i] != sizeof &arr[i][0]) and they
>> can't be used in the same places (you can, for example take the
>> address of one but not of the other).
>
> Think harder.

OK, but you'll have to help me if you think I've missed something.  I
really do think I get it.

I know you meant "in most expression contexts" and I did not say you
said anything wrong.  All I was saying is that it sometimes helps to
know the ways in which they *don't* mean the same thing.  Obviously
you disagree, and that is fine.  Only the OP can say which is more
helpful in "getting it".

>     *p = arr[i];
> means the same thing as
>     *p = (arr[i] + 0);
>
>     sizeof arr[i]
> does not mean the same thing as
>     sizeof (arr[i] + 0)

Of course not, and that is one reason why I'd be loath to say that
arr[i] and &arr[i][0] mean the same thing.

     sizeof &arr[i][0]

*does* mean the same thing as

     sizeof (&arr[i][0] + 0)

(as do '*p = &arr[i][0];' and '*p = &arr[i][0] + 0;').

All this does is to highlight that we expect different things from two
expressions that "mean the same".

-- 
Ben.