Re: Two dimensional array Question

pete wrote:

> Default User wrote:
> > Joe Wright wrote:
> > 
> > > mdh wrote:
> > 
> > > Perfect sense. All above is correct. Given 'int arr[2][13];', arr
> > > is an array 2 of array 13 of int. 26 consecutive ints.
> > > 
> > > > The exercise associated with this, used the construct
> > > > 
> > > > *p = arr[1 or 0 ] to point to either the "first" or "second"
> > > > row of the array. Does the compiler "know" where to point to
> > > > because it has been given this information by the declaration
> > > > of "13" in arr[2][13].  Hopefully this makes sense too!
> > > > 
> > > No. arr[0] is (the address of) an array 13 of int. 
> > 
> > No, it's not. It is an array 13 of int, not a pointer to one. arr
> > is a pointer to array 13 of int.
> 
> You just made the same mistake that you just corrected.

Yes, I did in a way. I was sloppy about context. It is correct that arr
is not a pointer, although it's converted to one in most contexts.

The code was correct, which it wasn't originally.


Thanks for clarifying my stab at i.





Brian