Problems with a simple linear search

I have an issue with a simple function that has to make a linear search 
for a key into an array.

If the key is found in the array, the function it has to return 1 to the 
caller and pass array index through a out parameter.

The issue is that the out parameter is not being updated.

If I return the position to the caller (instead to use a out parameter) 
all is ok.

But I would to use a boolean (1 or 0) value as return value to the 
caller: 1 stays for found, 0 stays for not found.

Thanks in advance and apologies for my bad english.

Here it is my piece of code.

/*** Code starts here ***/

/* Search for number 'x' in array v[] */
/* If 'x' found pass array position through 'pos' parameter */
/* and returns 1 to caller; else returns 0 */

int linsearch (int v[], int nmax, int x, int pos)
{

    int i;

    for (i=0; i<nmax; i++)
    {
       if(v[i]==x)
       {
          pos=i;    /* pass the index where found */
          return 1; /* returns 1 (found) */
       }
    }

    return 0; /* Exit from for...so returns 0 */
}

int main (void)
{
     int myvet[] = {5,4,3,2,1};

     int key = 2; /* Number to find */

     int index=0; /* Actual parameter that holds index of element */

     if(linsearch(myvet, 5, 2, index))		
	printf ("\nNumber %d found at position %d ", key, index);
     else
         printf ("\nNumber %d not found", key);

    return 0;
}

/*** Code ends here ***/