Re: Reading input problem

> On Thu, 08 May 2008 11:54:31 +0100, Ben Bacarisse wrote:


> I doubt anyone will write this for you.  It is a rather specific input
> routine and you will just have to work out a way to do it yourself.
> Do you plan using pseudo-code before starting to write the C?  You
> will need to, I think, because such an input routine is quite
> complex.

yes, it is complex *only* in C, I guess:

I can discard the words containing anything else than characters:


/* version 1.4 */

int getword( char *word, int max )
{
  int c, in_word;
  char *w, *w_begin;

  w_begin = word;
  w = word;
  in_word = 0;

  while( isspace( c = getchar() ))
    {
      continue;
    }


  if( isalpha( c ))
    {
      *w++ = c;
    }

  for( ; ( (c = getchar()) != EOF ) && --max ; ++w )
    {
      if( isalpha(c) )
	{
	  in_word = 1;
	  *w = c;
	}
      else if( c == EOF || isspace( c ) )
	{
	  *w = '\0';
	  in_word = 0;
	  return 1;
	}
      else
	{ 
	  if( in_word )
	    {
	      while( w != w_begin )
		{
		  *w-- = '\b';
		}
	      *w-- = '\b';
	    }
	}
    }



  *w = '\0';

  return word[0];
}
============= OUTPUT ==============
[arnuld@[EMAIL PROTECTED]
 C]$ gcc -ansi -pedantic -Wall -Wextra getword.c
[arnuld@[EMAIL PROTECTED]
 C]$ ./a.out 
Ben9
---------->  
9Ben
---------->  Ben
Be9n
---------->  n
[arnuld@[EMAIL PROTECTED]
 C]$ 



now only 2 things have remained:

1.) it does not discard the whole-word if the non-character comes as 1st
element or within the word like 9Ben or Be9n but it will discard Ben9
completely. So it is juts a half-implementation yet.


2.) as usual, does not discard characters more than 30 .   


any ideas on that ?



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