Re: Two dimensional array Question

Joe Wright wrote:

> mdh wrote:

> Perfect sense. All above is correct. Given 'int arr[2][13];', arr is
> an array 2 of array 13 of int. 26 consecutive ints.
> 
> > The exercise associated with this, used the construct
> > 
> > *p = arr[1 or 0 ] to point to either the "first" or "second" row of
> > the array. Does the compiler "know" where to point to because it has
> > been given this information by the declaration of "13" in
> > arr[2][13].  Hopefully this makes sense too!
> > 
> No. arr[0] is (the address of) an array 13 of int. 

No, it's not. It is an array 13 of int, not a pointer to one. arr is a
pointer to array 13 of int.

> The pointer 'p'
> must be declared to reflect this.
>
>   int (*p)[13];
> 
> Now p is a pointer to array 13 of int and..
> 
>   p = arr[0];
>
> ..makes sense.

Not to me.

   p = &arr[0];

Would. Or what the OP had:

   int *p;
   p = arr[0];





Brian