Re: When you declare an array of chars and store a string in it, where is the position of the null character \0? And what happens to the unused memory locations?

"arnuld" <sunrise@[EMAIL PROTECTED]
> ha scritto nel messaggio
news:pan.2008.05.07.03.11.12.336850@[EMAIL PROTECTED]
>> On Mon, 05 May 2008 15:17:44 -0700, Peter Nilsson wrote:
>
>> You need to be careful though of situations like...
>>
>>   char foo[5] = "dudes";
>>
>> C, unlike C++, allows such an initialisation. There is no
>> terminating null stored as there is no room for it.
>
>
> yes and you get garbage on the screen:
>
>
>
> #include <stdio.h>
>
>
> int main( void )
> {
>  char oye[2] = "ok";

is it not better  oye[4] = "ok"; ?
"ok" is o+k+\0

>  printf("%s\n", oye);
>
>  return 0;
> }
>
> ============= OUTPUT =============
> /home/arnuld/programs/C $ gcc -ansi -pedantic -Wall -Wextra test.c
> /home/arnuld/programs/C $ ./a.out
> okHßÿ¿3.L

here someone can see that "\0" is not copied from "ok" to oye[2]

> /home/arnuld/programs/C $
>
>
>
> it *accidentally* terminated because at some random place in memory it
> found the NULL ?
>
>
>
> -- 
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>