Re: Pointer question...last for the day? :-)

On May 5, 8:26=A0pm, Robert Gamble <rgambl...@[EMAIL PROTECTED]
> wrote:

> s and t are distinct objects, both of which point to the same place
> initially, for example, say they both point to the string "abc":
>
> =A0s
> =A0|
> =A0V
> +-+-+-+--+
> |a|b|c|\0|
> +-+-+-+--+
> =A0^
> =A0|
> =A0t
>
> After you execute s++, s points to the next character in the string:
>
> =A0 =A0s
> =A0 =A0|
> =A0 =A0V
> +-+-+-+--+
> |a|b|c|\0|
> +-+-+-+--+
> =A0^
> =A0|
> =A0t
>
> but t is unchanged. =A0If you modify the data that s points to, i.e.
> *s=3D'e' :
>
> =A0 =A0s
> =A0 =A0|
> =A0 =A0V
> +-+-+-+--+
> |a|e|c|\0|
> +-+-+-+--+
> =A0^
> =A0|
> =A0t
>
> and then access the data through t you will see "aec" since they both
> point into the same, now modified, object.


Thanks Robert. These things are so obvious once one understands them.