Re: strcpy question

mdh wrote:

> On May 5, 2:34 pm, Tomas O hEilidhe <t...@[EMAIL PROTECTED]
> wrote:
> 
> > A function cannot take an array as a parameter. If you do the
> > following:
> > 
> >  
> 
> Sorry if I was unclear...as this is what I was trying to say. In other
> words, a function that expects an array, will in fact actually
> receive a pointer as a parameter.

A function does not and cannot "expect" an array. Even if you write the
declaration to look like an array to a human reading it, the function
expects nothing of the sort. It expects and receives a pointer.

void f(int p[50]);
void f(int p[1]);
void f(int *p);

The above are identical to the compiler.

> So, what I was concentrating on was
> the syntax where a pointer that had an array allocated to it ( ie was
> not an array that had been converted to a pointer as an argument to a
> function) is just as  legal a  construct under  as passing an array
> itself.

You can't pass an array, so yes they are equally valid. 



Brian