Benoit Lefebvre <benoit.lefebvre@[EMAIL PROTECTED]
> writes:
> Weird subject you will say.. I didn't know what to put in there..
>
> Long story short, I'm changing the value of a variable from a
> function.. Nothing unusual there..
>
> How come the value of the "word" variable change when using the
> testfunct function? Am I sending a pointer to the word variable to
> this function or whatever ??
>
> I know it's a weird question.. especially that this is doing exactly
> what I need.. but I want to know if I'm doing it right and if not, how
> to make it work correctly.
>
> The program where this is going is checking a configuration text file
> and puts all the lines in a 2d char array for comparison later. Here
> is a simplified "extraction" of the code.
>
> ------
> #include <stdio.h>
> #include <strings.h>
>
> int testfunct (char *myword)
> {
> strcpy(myword,"hello");
>
> return 0;
> }
>
> int main (int argc, char *argv[])
> {
> char word[100];
>
> strcpy(word,"weeee");
> printf("WORD: %s\n", word);
> testfunct(word);
> printf("WORD: %s\n", word);
>
> return 0;
> }
Yes, you're sending a pointer to the function.
``word'' is an array object, so the argument to testfunct is an
expression of array type, which is implicitly converted to a pointer
to the array's first element. testfunct() then modifies the data that
its argument points to.
Read section 6 of the comp.lang.c FAQ, <http://www.c-faq.com/>.
--
Keith Thompson (The_Other_Keith) <kst-u@[EMAIL PROTECTED]
>
Nokia
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister"
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