Re: little/big endian question.

Martin <martindotounderscorebrien@[EMAIL PROTECTED]
> writes:

> On Sat, 03 May 2008 15:29:24 +0100, Charles Sullivan
> <cwsulliv@[EMAIL PROTECTED]
> wrote:
>>   hibyte = (svalue >> 8) & 0xFF;
>
> What's the point of the '& 0xFF'?

Well, it does make a difference if unsigned char has more than 8 bits
and unsigned short has more than 16.  If you've used a machine with
36, 18 and 9 bit types to implement octet-based processing, you do
this automatically.

-- 
Ben.