Re: little/big endian question.

Charles wrote:
)
) Suppose I have this code:
)
)   unsigned short svalue;
)   unsigned char  hibyte, lobyte;
)
)   svalue = 0xABCD;
)
)   hibyte = (svalue >> 8) & 0xFF;
)   lobyte = svalue & 0xFF;
)
) Will this result in the values of hibyte and lobyte being 0xAB and 0xCD
) respectively, regardless of whether the platform is little or big
endian?

Of course it will.  The ****ft operator doesn't care about endianess.


SaSW, Willem
-- 
Disclaimer: I am in no way responsible for any of the statements
            made in the above text. For all I know I might be
            drugged or something..
            No I'm not paranoid. You all think I'm paranoid, don't you !
#EOT