Re: program bug

"Robert Gamble" <rgamble99@[EMAIL PROTECTED]
> wrote in message 
news:2d73e006-fc0d-4ed7-ae1e-43535dea6140@[EMAIL PROTECTED]
> Not a ****table return value from main.
>
>>  }
>>  if (argv[1]=="b") {
>
> This isn't doing what you think it is.  This is comparing the address
> of first program argument to the address of the string literal "b"

    Was declaring b as a pointer to char proper? Or should a simple b of 
type char all that's needed?


> which will always be different.  Either use (strcmp(argv[1], "b") ==
> 0) or say:
>
> if (argv[1][0] == 'b') {
>
> which will compare the first letter of the first argument to the
> character constant b.

    I do not understand the above but it looks like a good way to write 
code. Why is a zero used as the second dimension of this array?

Bill