value of the constant expression 1<<(1?1:1) < 0x9999

Hello,

one of my C compiler (Keil C51) evaluates the constant expression
	1<<(1?1:1) < 0x9999
to the value 1.

// this returns 0, much to my surprise
unsigned char bug4_a(void)
	{
	return 1<<(1?1:1) < 0x9999;
	}

Can this find a satisfactory explanation under some definition of the
C language ?


Note: I still get 0 for

	return 1<<(1?1:1) < (unsigned)0x9999;

	return 1<<(unsigned char)(1?1:1) < 0x9999;

but I get 1 (as I expect) for

	return 1<<(1) < 0x9999;

	return (unsigned)1<<(1?1:1) < 0x9999;

	return 1u<<(1?1:1) < 0x9999;

	return 1<<(1?1:1) < 0x7777;

	return 1<<(1?1:1) == 2;

#if 1<<(1?1:1) < 0x9999
	return 1;
#else
	return 0;

TIA,

  Francois Grieu