Equation of a line (y=mx+c)

Hello,

i'm trying to implement "y=mx+c" into code to find the intercept of a
line.


#include <iostream.h>
#include <stdlib.h>
#include <math.h>

void main ()
{
	int Ax, Ay, Bx, By;
  	float Dx, Dy, Dist, Grad;

cout<<"Please enter the 'x' coordinate of the first point: "<<endl;
cin>>Ax;
cout<<"Please enter the 'y' coordinate of the first point: "<<endl;
cin>>Ay;
cout<<"Please enter the 'x' coordinate of the second point: "<<endl;
cin>>Bx;
cout<<"Please enter the 'y' coordinate of the second point: "<<endl;
cin>>By;

Dx=Ax-Bx;
Dy=Ay-By;
Grad= Dy/Dx;

cout<<"Gradient = "<<Grad<<endl;
}

is what i have so far to find "m".

Ex A(2,3) B(6,5)

As I understand the fomula would be;

y-Ay = Grad*(x-Ax)

substituing from A;

y-3=0.5*(x-2)
y-3=0.5x-1
y=0.5x+2

therefore "c" would be: 2

any idea on how i could code this?


G