char * memory leak

Quick question, how is a char * different than any other pointer? I've
never had this really elaborated.

Furthermore, is there a memory leak here (note this is just an example
not an actual implementation I'm using).

// name is an attribute of MyClass
void MyClass::SetName(char *n)
{
     char *newName = n;

     if ( SetToDefault == true )
     {
          newName = new char [7];


}