unnamed namespace and friend method

Can you declare a friend method if the method is defined in the unnamed 
namespace?

This is basically what I'd like to do:

namespace {
   MyClass *ptr;

   void fnc(unsigned long my_ul, short *my_s_ptr) {
     // blah blah whatever
     ptr->callme();
   }
}

class MyClass {
   friend void fnc(unsigned long, short *);

private:
   void callme();
}

g++ doesn't like this, but all is well if I put things in the global 
namespace.

I suppose I could create a fake namespace, but before I do, can I do 
what I want somehow? I also tried
friend void ::fnc(unsigned long, short *);
but that's no good either.

Thanks,

--John Ratliff