Re: octal error

On 2008-05-09 23:59, Victor Bazarov wrote:
> notahipee wrote:
>> This is all of it.
>> #include <iostream>
>> #include <ostream>
>> int main()
>> {
>>  int a;
>>
>>     cout << "enter a number " << endl;
>>     cin >> a;
>> switch (a)
>> {
>> case 00: cout << zero;
>> case 01: cout << zero one;
>> case 02: cout << zero two;
>> case 03: cout << zero three;
>> case 04: cout << zero four;
>> case 05: cout << zero five;
>> case 06: cout << zero six;
>> case 07: cout << zero seven;
>> case 08: cout << zero eight;
>> case 09: cout << zero ninne;
>> }
>>
>> return 0;
>> }
> 
> And what errors you get?  I believe you just need to drop the
> leading zero in all of your 'case' labels, but that's just
> a guess.
> 
> What is it you're trying to accomplish with the leading 0?
> Keep in mind that whatever form you enter your 'a' in, is
> getting converted into the internal representation which is
> just a value.  And if you want to put octal numbers in your
> 'case' labels, you shouldn't use '08' or '09' since they are
> not octal numbers, use '010' and '011'...

Even assuming that you drop the leading zeros (and fix the other issues)
the program will not work as expected since it will print "zero one"
even if the user just entered "1".

If you explain what you are trying to do (not getting the switch
statement to work, but rather why you have it to begin with) we might be
able to help you more.

-- 
Erik Wikström