Re: octal error

notahipee wrote:
> I have been trying to cin an number from 0 to 9 with a leading 0. For
> example 00 or 07. I was using a switch case.

You were using a switch case for what?

> switch (int)
  ^^^^^^^^^^^
That's a syntactically incorrect statement.

> {
> case 01: break;
> case 02: break;.....
> My problem arises at 08 and 09 because they are not octal.

What problem would that be?

> Is there
> any way to coerce the input variable to decimal despite it having a
> leading zero .

This is a glimmer of an actual problem you seem to be having... But
I am not seeing the alleged behaviour in the following program.

#include <iostream>
#include <ostream>
int main()
{
    int a = 666;
    std::cin >> a;
    std::cout << "you entered " << a << std::endl;
}

If I enter 08, it prints 'you entered 8'.  What's the problem?

V
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