Re: printing template argument

Venkat wrote:
> 
>> std::cout << typeid(C).name() << std::endl;
> 
> Doesn't it incur runtime cost?
> I'm wondering something that would be resolved at compile time.

With an expression C it may, but with a type name C, I don't see
anything in typeid(C) that requires any runtime operation;
the compiler knows the exact type C at compile-time, doesn't it?

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