Re: printing template argument

Alex wrote:
> On May 8, 5:31 am, Venkat <swara...@[EMAIL PROTECTED]
> wrote:
> 
>> (I don't want to pass a string argument representing the type to the
class.)
> 
> std::cout << typeid(C).name() << std::endl;

    While typeid(C).name() is guaranteed to be unique for each class C,
it is NOT guaranteed to be anything human-understandable.  This makes
the function rather useless, but that's what the standard says.

Joe Gottman

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