Re: How to convert a pointer to member function type to a const member one

> What is the best way to get a type TC from a type T where
>
> T is int(foo::*)(char)
> and
> TC is int(foo::*)(char) const

These two types are completely different. A better way to understand the
meaning of these types is:

T   ==>  int (foo::*)(foo obj, char c)
TC ==> int (foo::*)(const foo obj, char c)

Thus, it is not the member function pointer which is const or non-const.
It
is actually an argument of the member function that differs in const-ness.
This cannot be done with a static_cast or a const_cast.

You can use a reinterpret_cast to do this.

T x = &foo::abc;
TC y = reinterpret_cast<TC>(x);

but be careful when using the result of reinterpret_cast.

Hope this helps,
Devdatt


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