Re: Hexadecimal and bitwise operations

On 19 abr, 05:01, "Hak...@[EMAIL PROTECTED]
" <Hak...@[EMAIL PROTECTED]
> wrote:
> Maybe this is just my lack of experience with working with hex, but...
>
> I was asked to produce an M-tree class using unsigned ints in hex to
> traverse through and find nodes. The thing I'm having trouble working
> out is, I was given (on paper) 25E1 & 0010 = 00E0, but when I tried it

This doesn't look right to me. 0x25E1 & 0x0010 == 0x0
If you want want your result to be 0x00e0, the operation should be
0x25E1 & 0x00f0

> on my computer, I found C++ converting it all to binary and producing
> 0x4 & 0x3 = 100 & 011 = 0.

Maybe you've forgot the initial 0x to indicate you're writing in
hexadecimal. So 25E1 is interpreted as a double and 0010 is
interpreted as an integer number writen  in octal.

> Obviously, that's not helpful. How can I take my hex numbers and do
> the & operation? Or maybe my question is wrong--how can I access the
> n'th digit?

If you want the n'th hexadecimal digit, you want to do:

(number >> (n * 4)) & 0x0f




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