How does an assignment operator work? Following the code that I give below,
I notice it isn't clear how the base operator works. I am not sure. It
seems
to me that there is a copy constructor formed that is used after the '='
is
call. Cout <<
"assigment operator ", prints first the at the return the copy constuctor
is
called. Is there a copy constructor created before the print statement is
executed or is it during the return a.s? Or what is going on?
Here is the code:
#ifndef H_H
#define H_H
# include <iostream>
using namespace std;
class base
{
private:
char s;
public:
base( ){}
base(const char a ):s(a) {cout << "construction with arg " << int(a)
<<
endl;}
base(const base & a){cout <<"copy constructor " << int(a.s) << endl;}
base operator=(const base & a){cout << "assignment operator " << a.s
<<
endl; return a.s;}
~base( ) {cout << "destruction" << endl;}
};
#endif
#include "h.h"
int main()
{
base b3;
base b1 = 'x'; // is equivalent to base b1('x');
base b2 = b1; //copy constructor is called Is seen as Base b2(b1)
b3 = b1; // assignment operator called and copy constructor is called
return 0;
}
Jeff
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