Re: copy constructor not being called

> In the following code, I expect the copy constructor to be called as
> per the textbooks but it is not being called. Could you please tell me
> why? g++ version 4.1.2
>
> # include <iostream>
> using namespace std;
> class base
> {
>    char s;
> public:
>    base( ){cout<< "construction" << endl;}
>    base(const char a ) {cout << "construction with arg" << endl;}
>    base(const base & a){cout <<"copy constructor" << endl;}
>    base & operator=(const base & a){cout << "assignment operator" <<
> endl;}
>    ~base( ) {cout << "destruction" << endl;}
>
> };
>
> main ( )
> {
>    base b1 = 'x'; //why copy constructor not called here?
>    base b2 = b1; //copy constructor is called
>
> }
>
> the line base b1 = 'x', as per my understanding must create a
> tem****ary object and then it should be copied to b1. But only the
> constructor with argument is called in this example when executed.
>
> Could you please explain why?

It must not create a tem****ary object. Because one of the constructors
take an char, that constructor will be called.
base b1 = 'x' is equivalent with base b1('x'); (so it no assignment is
taking place).


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