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Programming > Basic Misc > Re: ARCTANXY Fu...
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Re: ARCTANXY Function

by "Tom Lake" <tlake@[EMAIL PROTECTED] > Mar 4, 2008 at 01:02 PM

"David Williams" <david.williams@[EMAIL PROTECTED]
> wrote in message 
news:1204646588.877.1204581661@[EMAIL PROTECTED]
>-> I'm trying to ****t some Zeno programs over to BASIC and I'm stuck on
the
> -> Zeno function ARCTANXY(x,y).  According to the Zeno manual,
> -> it should be equal to ATN(y/x) when x and y are both non-zero.
> -> I created a BASIC function that does that but the results don't match
> -> the Zeno output.  Does anyone here know exactly what calculation to
> -> use for ARCTANXY?  TIA
>
> Here's how I usually code it in QBasic.
>
> FUNCTION Ang(X, Y)
>  SELECT CASE SGN(X)
>    CASE 1: Ang = ATN(Y / X)
>    CASE -1: Ang = ATN(Y / X) + PI
>    CASE ELSE: Ang = SGN(Y) * PI / 2
>  END SELECT
> END FUNCTION
>
> Of course PI has to be pre-defined.
>
> The FUNCTION produces an angle in the range -PI/2 <= Ang < 3*PI/2.
> That's the complete circle, but if you want to adjust the range to,
> e.g., 0 to 2*PI, you'd have to add a bit of fiddling.
>
> Note that Ang is *not* equal to ATN(Y/X) if X is negative. ATN doesn't
> produce the complete circle of values.

Most implementations give
ATAN2(-5,-5) = -2.35619

but yours gives

Ang(-5,-5) = 3.926990

Any idea why?

Tom L
 




 2 Posts in Topic:
ARCTANXY Function
david.williams@[EMAIL PRO  2008-03-04 10:03:08 
Re: ARCTANXY Function
"Tom Lake" <  2008-03-04 13:02:03 

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tan12V112 Sat Jul 26 2:38:05 CDT 2008.