Re: How to pass UNIX variable into awk?

In article <ftg14s$392$1@[EMAIL PROTECTED]
>,
RC  <raymond.chui@[EMAIL PROTECTED]
> wrote:
>RC wrote:
>> myvariable="hello"
>> 
>> cat my file, if first field match "hello", then print whole line
>> 
>> I tried
>> 
>> cat myfile.txt | awk -F: '$1 ~ /$myvariable/ {print $0}'
>> 
>> but doesn't work, I also tried double $ like $1 ~ /$$myvariable/
>> still no luck.
>
>I found the answer from
>http://www.faqs.org/faqs/unix-faq/faq/part3/section-12.html
>
>cat myfile.txt | awk -F: '$1 ~ /'"$myvariable"'/ {print $0}'
>
>Where '" are single quote and double quotes
>       "' are double quotes and single quote

Good for you.

Now, of course, the nitpickers will come along and point out:
	1) UUOC
	2) UUO$0
	3) In the nanny-state, you aren't supposed to do it this way.
	    They have this wacky idea that it is safer/better to use -v.
	    Hint: It isn't.