Re: rename based on file name

Ted Davis escreveu:
> On Wed, 26 Mar 2008 05:16:13 -0700, tcdrake wrote:
> 
>> I think one option is to have a piece of code which goes through the
>> directory and makes a list of all the files. Then use that list to
rename
>> the unzipped files based on the list. I just not sure how to implement
it.
>> Any ideas?
> 
> In your example code, you seem to be trying to rename the same files
twice
> to different names - that doesn't work.  Also, you should not use
getline
> that way - it's so much better to pass the file name as an argument and
> let awk take care of the file. 
> 

Since again we're heading half off topic here...

> In a batch file:
>   for %%A in (*.dbf) do (
> 	rename code here
> 	%%~nA is the file's base name without the extesnion
> 	%%~xA is the extension
> 	%%~dA is the drive letter and colon
> 	%%~pA is the directory
>   )
> 
> The only thing you need awk for is to generate the various date strings.

> Your approach to generating date strings is *way* too complicated - it's
> better to use
> 
> batch file
>   for /f "tokens=1,2" %%A in ('awk "BEGIN{print
>  strftime(\"%%Y%%m%%d\",systime()-86400) \" \"
>  strftime(\"%%Y%%m%%d\",systime()-2*86400)}"') do ( set yesterday=%%A&
set
>  daybefore=%%B)
> 
> All one line.  Then the two dates are in the named environment variables
> in YYYYMMDD format.  I don't see any reason for the daybefore, you your
> code generates it.

The OP can elide all the AWK contortion using an appropriate port of the 
unix utility date for its OS (which I surmise is a variety of Windows 
due the use of winzip.exe):


C:\>c:\usr\local\wbin\date.exe
Wed Mar 26 18:06:59 BST 2008

C:\>c:\usr\local\wbin\date.exe -d yesterday
Tue Mar 25 18:07:07 BST 2008

C:\>c:\usr\local\wbin\date.exe -d "2 days ago"
Mon Mar 24 18:07:13 BST 2008

These dates can be formated as above:

C:\>c:\usr\local\wbin\date.exe +%Y%m%d
20080326

C:\>c:\usr\local\wbin\date.exe-d yesterday +%Y%m%d
20080325

C:\>c:\usr\local\wbin\date.exe -d "2 days ago" +%Y%m%d
20080324

HTH