You cannot pass an array as an argument to a function. However, variables
in
awk are in general global, so you can use the actual variable name in the
function.
Rajan
"Hermann Peifer" <peifer@[EMAIL PROTECTED]
> wrote in message
news:47DBAE29.4050709@[EMAIL PROTECTED]
> Hi All,
>
> The Gawk man page says:
> > Starting with version 3.1.5, as a non-standard extension,
> > with an array argument, length() returns the number
> > of elements in the array.
>
> It looks like Gawk's length(array) extension does not work inside
> functions. Is this a bug or feature or am I missing something? See the
> example below. I am using GNU Awk 3.1.6
>
> $ cat testdata
> CD NAME
> AT Austria
> BG Bulgaria
> CH Switzerland
> DE Germany
> EE Estonia
> FR France
> GR Greece
>
> $ cat test.awk
>
> # Populate array
> NR > 1 { array[$1] = $2 }
>
> # Print array length and call function A
> END { print "array:",length(array) ; A(array) }
>
> function A(array_A) { print "array_A:", length(array_A) }
>
> $ gawk -f test.awk testdata
> array: 7
> gawk: test.awk:8: (FILENAME=data FNR=8) fatal: attempt to use array
> `array_A (from array)' in a scalar context
>
> BTW, there is no such error if I have asort(array_A) or asorti(array_A)
> inside the function.
>
> Hermann
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