Re: compare numbers behaves strange...

On 12 mar, 14:40, di98mase <di98m...@[EMAIL PROTECTED]
> wrote:
> Hi
>
> I have a file with numbers in it. My program reads the values and
> compare them and depending on the value I increment a counter. what I
> have seen is that the evaluation fails. This is an extract of my
> numbers:
>
> 7
> 7
> 7
> 34
> 92
> 111
> 294
> 121
> 142
>
> This is parts of my program that checks the value (ms) read from the
> file and increments the counters
>
> =A0 =A0 =A0 if( ms =3D=3D 18) t18++;
> =A0 =A0 =A0 if( ms =3D=3D 19) t19++;
> =A0 =A0 =A0 if( ms >=3D 20 && ms < 30)
> =A0 =A0 =A0 {
> =A0 =A0 =A0 =A0 =A0print ms;
> =A0 =A0 =A0 =A0 =A0t20++;
> =A0 =A0 =A0 }
> =A0 =A0 =A0 if( ms >=3D 30 && ms < 40) t30++;
> =A0 =A0 =A0 if( ms >=3D 40 && ms < 50) t40++;
> =A0 =A0 =A0 if( ms >=3D 50 && ms < 60) t50++;
> =A0 =A0 =A0 if( ms >=3D 60 && ms < 70) t60++;
>
> As you can see I dont have any numbers between 20 and 30 but I still
> get an increment for the t20 counter. When I print the value it is
> "294". Why do I have this behaviour?

You should probably do like this :

ms2 =3D int(ms/10)
Tab[ms2]++

# Having the result
END {
  for ( x in Tab ) {
    print x "\t" Tab[x]

}