Re: How to filter out lines?

Viatly wrote:
> Given a stdout of some prog, I have to filter out 2-line blocks of
> text, where the first line contains "marker1" and the second line
> contains "marker2".
> Thus, for the following output
>
> some text..
> more text...marker1...moretext
> more text...marker2...moretext
> more text..
> more text...marker1...moretext
> more text..
> more text...marker2...moretext
> more text...
>
> after applying the filter I shell get
>
> some text..
> more text..
> more text...marker1...moretext
> more text..
> more text...marker2...moretext
> more text...
>
> For one-line case grep whould be just sufficient:
>
> ./prog | grep -v marker1
>
> however for multiline patterns I think grep is not a right choice. How
> it can be done with awk/sed?

ruby -e'puts gets(nil).gsub(/^.*marker1.*\n.*marker2.*\n/,"")'