Re: Question about a programme

On Feb 18, 2:14=A0pm, Ed Morton <mor...@[EMAIL PROTECTED]
> wrote:
> On 2/18/2008 6:57 AM, Spiros Bousbouras wrote:
>
>
>
>
>
> > On page 194 of "Effective AWK programming" we see the
> > following programme:
>
> > # rewind.awk --- rewind the current file and start over
> > function rewind( =A0 =A0i)
> > {
> > =A0 =A0 # ****ft remaining arguments up
> > =A0 =A0 for (i =3D ARGC; i > ARGIND; i--)
> > =A0 =A0 =A0 =A0 ARGV[i] =3D ARGV[i-1]
> > =A0 =A0 # make sure gawk knows to keep going
> > =A0 =A0 ARGC++
> > =A0 =A0 # make current file next to get done
> > =A0 =A0 ARGV[ARGIND+1] =3D FILENAME
> > =A0 =A0 # do it
> > =A0 =A0 nextfile
> > }
>
> > Isn't the statement ARGV[ARGIND+1] =3D FILENAME
> > superfluous ? In the loop when i gets the
> > value ARGIND + 1 then the assignment
> > ARGV[ARGIND + 1] =3D ARGV[ARGIND] will be executed
> > and ARGV[ARGIND] always has the same value as
> > FILENAME
>
> But what if the current file is the last one? Then i =3D ARGC =3D ARGIND
a=
t the
> start of the loop...<snip>

At the start of the loop for the last file
i =3D=3D ARGC =3D=3D ARGIND + 1