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Programming > Assembly 370 > Re: call instru...
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Re: call instruction

by "Sven Pran" <no.direct@[EMAIL PROTECTED] > Sep 14, 2006 at 09:02 PM

Wrong group - this is for S/370 /IBM mainframes)
Sven

"Wendy E. McCaughrin" <wemccaug@[EMAIL PROTECTED]
> wrote in message 
news:eec6fq$n02$1@[EMAIL PROTECTED]
> CN99 <leon800219@[EMAIL PROTECTED]
> wrote:
> : Hi all:
>
> : Can anybody tell me what the value will be in ax, after the 'call' 
> excuted,
> : and why? Thanks!
> : To me:
> : pop ax // ax = 8
> : add ax, ax // ax = 16
> : pop bx // bx = 1000
> : add ax, bx // ax = 1000 + 16 -> 1016?
>
> Looks like you are at segment = 10x1000, but at what offset?
> I am guessing this is a DOS program, with origin offset = 0x100.
>
> : 1000:0        b8 00 00          mov ax, 0
> : 1000:3        9A 09 00 00 10    call far ptr s
>
> This sets [stack-top] = return-address 0x0100 + 8 = 0x0108.
>
> : 1000:8        8 40              inc ax
> : 1000:9        9 58              s:pop ax
> :                                   add ax, ax
> :                                   pop bx
> :                                   add ax, bx
>
> At label s, the return-address (0x0108) is popped into AX. What
> was [stack-top] before the call? That determines contents of BX.
>
 




 4 Posts in Topic:
call instruction
"CN99" <leon  2006-05-22 22:06:46 
Re: call instruction
SkippyPB <swiegand@[EM  2006-05-22 12:45:20 
Re: call instruction
"Wendy E. McCaughrin  2006-09-14 18:19:38 
Re: call instruction
"Sven Pran" <  2006-09-14 21:02:47 

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