call instruction

Hi all:

    My question is what value AX will contains after the execution
following 
code?

144D:0000 B84C14        MOV     AX,144C
144D:0003 8ED0          MOV     SS,AX
144D:0005 BC1000        MOV     SP,0010
144D:0008 8ED8          MOV     DS,AX
144D:000A B80000        MOV     AX,0000
144D:000D FF160E00      CALL    [000E]
144D:0011 40            INC     AX
144D:0012 40            INC     AX
144D:0013 40            INC     AX

Here's my description:
CALL    [000E] // Will change IP to 16, in HEX 10. So execution jump to 
execute 00(end byte of FF160E00)?
              // (I thought execution was supposed to jump to 0, 3, 5, 8 ~

13, but not 10)
             // then next the first "INC     AX" will be executed? So AX 
turn out to be 3 ?