Hello all,
I have found a conflict in parsing C99 which arises from the fact that
after a mult_expr a '*' (according to bison) can come up which means
that it can either reduce mult_expr or shift the '*' for yet another
multiplication.
Now, * comes up as a unary operator and in the pointer definition but
I can't find how or where they can follow a multiplication. Can
someone let me know either how to solve this shift/reduce conflict or
give me a concrete example where a * comes after a multiplication and
is not a multiplication operator?
Cheers,
--
Paulo Jorge Matos - pocm at soton.ac.uk
http://www.personal.soton.ac.uk/pocm
PhD Student @[EMAIL PROTECTED]
ECS
University of Southampton, UK
