Bug Report: Bogus built-in operator considered during overload resolution

Hi,

This is essentially a re-post of a message from a few days ago, with a
more
eye-catching subject line.

According to section 13.6 of the standard, an operator of the form

   T& operator*(T*)

should be considered during overload resolution for an expression of the
form *x
where x has class type, only if T is a function type or an object type.
Since
void is not an object type, the no operator of the form operator*(void*)
should
be considered.

However, I'm getting a complaint of ambiguity from Codewarrior 9.3 and 9.4
relating to an expression *x, where x has type std::istream, in which one
of the
two candidate functions is described as operator*(void*). (See
http://tinyurl.com/626kr).

The following test program is a simplification of the code which leads to
the
above error.

    struct Thing {
        operator void* () const;
    };

    struct any {
        template<class T>
        any(T const&);
    };

    char operator*(any const&);

    int main()
    {
        Thing t;
        *t;
    }

Any help would be greatly appreciated.

Best Regards,
Jonathan