Actually I=B4ll ask one more thing. I have another
situation at the program like this, and use the same idea. I have to
call int61 to save what=B4s in bl:
071A:00000D37 50 PUSH AX
071A:00000D38 51 PUSH CX
071A:00000D39 52 PUSH DX
071A:00000D3A 56 PUSH SI
071A:00000D3B 57 PUSH DI
071A:00000D3C 33 DB XOR BX,BX
071A:00000D3E B9 F0 03 MOV CX,03F0
071A:00000D41 BA 83 07 MOV DX,0783
071A:00000D44 B3 03 MOV BL,03
071A:00000D46 E8 E7 00 CALL (+00E7)
071A:00000D49 8A 1C MOV BL,[SI]
071A:00000D4B E8 E2 00 CALL (+00E2)
071A:00000D4E 02 FB ADD BH,BL (Change this
to CD 61) <<<<<<<<<<<<<<
071A:00000D50 46 INC SI
071A:00000D51 E2 EE LOOP (-12)
071A:00000D53 5F POP DI
071A:00000D54 5E POP SI
071A:00000D55 5A POP DX
071A:00000D56 59 POP CX
071A:00000D57 58 POP AX
071A:00000D58 C3 RET
Again, I=B4ll have to do that task add bh, bl before returning to the
main program. Question: When i get into isr 61h will bx be with the
same value as in the main program, so I can read bl, do the sum and
save bx again?=20
Tks again
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