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Location of the atoms of the Mandelbrot set

by "Henning Kühn" <atomsiggi@[EMAIL PROTECTED] > Jan 23, 2007 at 10:56 PM

I am looking for an explanation for the location of the atoms which are 
attached to the boundary of the cardioid of the Mandelbrot set.

For any rational numbers phi=n/m (with n,m natural numbers) an atom with
an 
attractive orbit of the period m is attached to the main cardioid at the 
point c=exp(i*phi)/2-exp(i*2*phi)/4. But how can we derive this fact?

The boundary of the main (period one) cardioid can be derived by using the

condition for indifferent fixed points:

Abs(d(f(z))/dz)=Abs(2z)=1 (with f(z)=z^2+c)

So we can write

z=exp(i*phi)/2

together with the fixed point equation

z=z^2+c

we get

c=exp(i*phi)/2-exp(i*2*phi)/4

This curve drawn in the complex plane results in the heart-like shape of
the 
cardioid as you can see for example here:

http://en.wikipedia.org/wiki/Mandelbrot_set

The boundary of the period two bud

Abs(1+c)=1/4

corresponding to a circle with radius 1/4 centered at c=-1 can be derived
in 
a similar way.

But how can we derive the general case that an atom with an attractive
orbit 
of the period m is attached to the main cardioid at the point 
c=exp(i*n/m)/2-exp(i*2*n/m)/4?

Many thanks for answers.

Henning




 2 Posts in Topic:
Location of the atoms of the Mandelbrot set
"Henning Kühn"   2007-01-23 22:56:43 
Re: Location of the atoms of the Mandelbrot set
"Henning Kühn"   2007-01-24 22:28:35 

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tan12V112 Mon May 12 6:14:54 CDT 2008.