Re: Allocating memory with "new"

barss wrote:
> On Apr 23, 8:00 pm, "sk_usenet" <sometechyguy at gmail dot com> wrote:
>> "Pat" <pkelecy@[EMAIL PROTECTED]
> wrote in message
>>> I have a question about the new operator.  The syntax for it is:
>>> int * pointer = new int;
>>> which says that "pointer" points to a type int variable.
>>> My question is why is "int" needed twice?  I know it's needed from a
>>> syntax standpoint, but I don't understand what additional information
the
>>> second int really provides.  Doesn't the first int already tell you
that
>>> an int type value is going to be stored at the "pointer" address?
>> What about arrays?
>>  int *p = new int[10];
>>
>>> Can you ever have,
>>> int * pointer = new double
>> No, realize that new operator is returning a double*, and heance trying
to
>> assign to an int* is not legal.
>>
>>> or something like that?
>>> Thanks for any feedback on this.
>> --http://techytalk.googlepages.com
> 
> never mind. You use "int" to store pointer. This trick will be work
> for 32 bit platforms because size of any pointer will be 4 bytes. But
> for 64 bit platforms you will have a problem, because size of any
> pointer will be more than 4 bytes. You can see note also about pointer
> to int conversion when compiling.

Please explain what this has to do with the question. Nothing above said 
anything about storing pointers in ints.